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difficulty 3/5

Backpropagation

Definition

The chain rule applied backwards through a computational graph. One traversal produces the derivative with respect to every parameter, at roughly the cost of one forward pass.

Formula
∂J∂W(1)=prod ⁣(∂J∂z,∂z∂W(1))=∂J∂z x⊤\frac{\partial J}{\partial \mathbf{W}^{(1)}} = \mathrm{prod}\!\left(\frac{\partial J}{\partial \mathbf{z}}, \frac{\partial \mathbf{z}}{\partial \mathbf{W}^{(1)}}\right) = \frac{\partial J}{\partial \mathbf{z}}\,\mathbf{x}^{\top}

Intuition

A network with sixty thousand parameters needs sixty thousand derivatives, one per parameter, at every step. The obvious method — nudge a parameter, see what happens to the loss, repeat — needs two forward passes per parameter. That is a hundred and twenty thousand evaluations for one update.

Backpropagation gets all sixty thousand from one traversal of the network in reverse. Not one per parameter; one, total. The worked example measures the difference at 73,432×, and the gap grows with the parameter count, which is why this algorithm is what makes deep learning possible rather than merely definable.

The mechanism is not exotic. It "traverses the network in reverse order, from the output to the input layer, according to the chain rule from calculus" [1, §5.3.3]. What makes it fast is the direction.

Formal definition

How it works

Where it's used

Why & when

Worked example

Pitfalls

Check yourself

3 questions

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Sources

  1. Zhang, Lipton, Li, Smola. Dive into Deep Learningbook · retrieved 2026-09-12https://d2l.ai/chapter_multilayer-perceptrons/backprop.html
  2. Baydin, Pearlmutter, Radul, Siskind. Automatic Differentiation in Machine Learning: a Survey (2018)paperhttps://ar5iv.labs.arxiv.org/html/1502.05767

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